Base | Representation |
---|---|
bin | 10100101111000010… |
… | …01110011100011001 |
3 | 1001201210211101211221 |
4 | 22113201032130121 |
5 | 140244243112441 |
6 | 5040341252041 |
7 | 542601321340 |
oct | 122741163431 |
9 | 31653741757 |
10 | 11132004121 |
11 | 47a27a9507 |
12 | 21a8104021 |
13 | 10853953b4 |
14 | 778632b57 |
15 | 4524668d1 |
hex | 29784e719 |
11132004121 has 4 divisors (see below), whose sum is σ = 12722290432. Its totient is φ = 9541717812.
The previous prime is 11132004101. The next prime is 11132004127. The reversal of 11132004121 is 12140023111.
11132004121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 12140023111 = 71 ⋅170986241.
It is a cyclic number.
It is not a de Polignac number, because 11132004121 - 29 = 11132003609 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11132004095 and 11132004104.
It is not an unprimeable number, because it can be changed into a prime (11132004127) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 795143145 + ... + 795143158.
It is an arithmetic number, because the mean of its divisors is an integer number (3180572608).
Almost surely, 211132004121 is an apocalyptic number.
It is an amenable number.
11132004121 is a deficient number, since it is larger than the sum of its proper divisors (1590286311).
11132004121 is an equidigital number, since it uses as much as digits as its factorization.
11132004121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1590286310.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 11132004121 its reverse (12140023111), we get a palindrome (23272027232).
The spelling of 11132004121 in words is "eleven billion, one hundred thirty-two million, four thousand, one hundred twenty-one".
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