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1113292096593 = 3371097365531
BaseRepresentation
bin10000001100110101011…
…000010100010001010001
310221102121020111020101120
4100030311120110101101
5121220010234042333
62211234521152453
7143301262453515
oct20146530242121
93842536436346
101113292096593
1139a165401996
1215b91b32b729
1380ca183b5a1
143bc5294a145
151de5c89edb3
hex10335614451

1113292096593 has 4 divisors (see below), whose sum is σ = 1484389462128. Its totient is φ = 742194731060.

The previous prime is 1113292096591. The next prime is 1113292096607. The reversal of 1113292096593 is 3956902923111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1113292096593 - 21 = 1113292096591 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1113292096591) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 185548682763 + ... + 185548682768.

It is an arithmetic number, because the mean of its divisors is an integer number (371097365532).

Almost surely, 21113292096593 is an apocalyptic number.

It is an amenable number.

1113292096593 is a deficient number, since it is larger than the sum of its proper divisors (371097365535).

1113292096593 is an equidigital number, since it uses as much as digits as its factorization.

1113292096593 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 371097365534.

The product of its (nonzero) digits is 787320, while the sum is 51.

The spelling of 1113292096593 in words is "one trillion, one hundred thirteen billion, two hundred ninety-two million, ninety-six thousand, five hundred ninety-three".

Divisors: 1 3 371097365531 1113292096593