111333120000001 has 4 divisors (see below), whose sum is σ = 111333695912404. Its totient is φ = 111332544087600.

The previous prime is 111333119999977. The next prime is 111333120000019. The reversal of 111333120000001 is 100000021333111.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 88913131749376 + 22419988250625 = 9429376^2 + 4734975^2 .

It is a cyclic number.

It is not a de Polignac number, because 111333120000001 - 2¹³ = 111333119991809 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 111333120000001.

It is not an unprimeable number, because it can be changed into a prime (111333120001001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 287666130 + ... + 288052891.

It is an arithmetic number, because the mean of its divisors is an integer number (27833423978101).

Almost surely, 2^{111333120000001} is an apocalyptic number.

It is an amenable number.

111333120000001 is a deficient number, since it is larger than the sum of its proper divisors (575912403).

111333120000001 is an equidigital number, since it uses as much as digits as its factorization.

111333120000001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 575912402.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 111333120000001 its reverse (100000021333111), we get a palindrome (211333141333112).

The spelling of 111333120000001 in words is "one hundred eleven trillion, three hundred thirty-three billion, one hundred twenty million, one", and thus it is an aban number.