1113331214003 has 4 divisors (see below), whose sum is σ = 1113539435400. Its totient is φ = 1113122992608.

The previous prime is 1113331213991. The next prime is 1113331214111. The reversal of 1113331214003 is 3004121333111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1113331214003 - 2³⁴ = 1096151344819 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1113331214003.

It is not an unprimeable number, because it can be changed into a prime (1113331214603) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 104102678 + ... + 104113371.

It is an arithmetic number, because the mean of its divisors is an integer number (278384858850).

Almost surely, 2^{1113331214003} is an apocalyptic number.

1113331214003 is a deficient number, since it is larger than the sum of its proper divisors (208221397).

1113331214003 is an equidigital number, since it uses as much as digits as its factorization.

1113331214003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 208221396.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 1113331214003 its reverse (3004121333111), we get a palindrome (4117452547114).

The spelling of 1113331214003 in words is "one trillion, one hundred thirteen billion, three hundred thirty-one million, two hundred fourteen thousand, three".