11134012433 has 4 divisors (see below), whose sum is σ = 11134267248. Its totient is φ = 11133757620.

The previous prime is 11134012429. The next prime is 11134012441. The reversal of 11134012433 is 33421043111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33421043111 = 19 ⋅1759002269.

It is a cyclic number.

It is not a de Polignac number, because 11134012433 - 2² = 11134012429 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11134012399 and 11134012408.

It is not an unprimeable number, because it can be changed into a prime (11134012133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43403 + ... + 155408.

It is an arithmetic number, because the mean of its divisors is an integer number (2783566812).

Almost surely, 2^11134012433 is an apocalyptic number.

It is an amenable number.

11134012433 is a deficient number, since it is larger than the sum of its proper divisors (254815).

11134012433 is an equidigital number, since it uses as much as digits as its factorization.

11134012433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 254814.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 11134012433 its reverse (33421043111), we get a palindrome (44555055544).

The spelling of 11134012433 in words is "eleven billion, one hundred thirty-four million, twelve thousand, four hundred thirty-three".