111343000001 has 4 divisors (see below), whose sum is σ = 111343878912. Its totient is φ = 111342121092.

The previous prime is 111342999983. The next prime is 111343000009. The reversal of 111343000001 is 100000343111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 100000343111 = 1811 ⋅55218301.

It is a cyclic number.

It is not a de Polignac number, because 111343000001 - 2¹⁴ = 111342983617 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 111343000001.

It is not an unprimeable number, because it can be changed into a prime (111343000009) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 209225 + ... + 516198.

It is an arithmetic number, because the mean of its divisors is an integer number (27835969728).

Almost surely, 2^111343000001 is an apocalyptic number.

It is an amenable number.

111343000001 is a deficient number, since it is larger than the sum of its proper divisors (878911).

111343000001 is an equidigital number, since it uses as much as digits as its factorization.

111343000001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 878910.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 111343000001 its reverse (100000343111), we get a palindrome (211343343112).

The spelling of 111343000001 in words is "one hundred eleven billion, three hundred forty-three million, one", and thus it is an aban number.