1113433104011 has 4 divisors (see below), whose sum is σ = 1161843238992. Its totient is φ = 1065022969032.

The previous prime is 1113433103899. The next prime is 1113433104059. The reversal of 1113433104011 is 1104013343111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1113433104011 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (23), and also a Moran number because the ratio is a prime number: 48410134957 = 1113433104011 / (1 + 1 + 1 + 3 + 4 + 3 + 3 + 1 + 0 + 4 + 0 + 1 + 1).

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1113433104071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24205067456 + ... + 24205067501.

It is an arithmetic number, because the mean of its divisors is an integer number (290460809748).

Almost surely, 2^{1113433104011} is an apocalyptic number.

1113433104011 is a deficient number, since it is larger than the sum of its proper divisors (48410134981).

1113433104011 is an equidigital number, since it uses as much as digits as its factorization.

1113433104011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48410134980.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 1113433104011 its reverse (1104013343111), we get a palindrome (2217446447122).

The spelling of 1113433104011 in words is "one trillion, one hundred thirteen billion, four hundred thirty-three million, one hundred four thousand, eleven".