11135445041 has 4 divisors (see below), whose sum is σ = 12726222912. Its totient is φ = 9544667172.

The previous prime is 11135445029. The next prime is 11135445047. The reversal of 11135445041 is 14054453111.

11135445041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14054453111 = 8377 ⋅1677743.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11135445041 is a prime.

It is a super-2 number, since 2×11135445041² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11135444995 and 11135445013.

It is not an unprimeable number, because it can be changed into a prime (11135445047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 795388925 + ... + 795388938.

It is an arithmetic number, because the mean of its divisors is an integer number (3181555728).

Almost surely, 2^11135445041 is an apocalyptic number.

It is an amenable number.

11135445041 is a deficient number, since it is larger than the sum of its proper divisors (1590777871).

11135445041 is an equidigital number, since it uses as much as digits as its factorization.

11135445041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1590777870.

The product of its (nonzero) digits is 4800, while the sum is 29.

Adding to 11135445041 its reverse (14054453111), we get a palindrome (25189898152).

The spelling of 11135445041 in words is "eleven billion, one hundred thirty-five million, four hundred forty-five thousand, forty-one".