Base | Representation |
---|---|
bin | 110011110110101001… |
… | …0101000010001010011 |
3 | 101122102112120121222222 |
4 | 1213231102220101103 |
5 | 3311023422004011 |
6 | 123053401451255 |
7 | 11021326100444 |
oct | 1475522502123 |
9 | 348375517888 |
10 | 111355266131 |
11 | 4325316566a |
12 | 196b87a0b2b |
13 | a668215225 |
14 | 55651ad2cb |
15 | 2d6b0a2ddb |
hex | 19ed4a8453 |
111355266131 has 4 divisors (see below), whose sum is σ = 111518305272. Its totient is φ = 111192226992.
The previous prime is 111355266109. The next prime is 111355266137. The reversal of 111355266131 is 131662553111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111355266131 is a prime.
It is a super-2 number, since 2×1113552661312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 111355266091 and 111355266100.
It is not an unprimeable number, because it can be changed into a prime (111355266137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81518546 + ... + 81519911.
It is an arithmetic number, because the mean of its divisors is an integer number (27879576318).
Almost surely, 2111355266131 is an apocalyptic number.
111355266131 is a deficient number, since it is larger than the sum of its proper divisors (163039141).
111355266131 is an equidigital number, since it uses as much as digits as its factorization.
111355266131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 163039140.
The product of its digits is 16200, while the sum is 35.
The spelling of 111355266131 in words is "one hundred eleven billion, three hundred fifty-five million, two hundred sixty-six thousand, one hundred thirty-one".
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