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1114012131131 = 5041212209811
BaseRepresentation
bin10000001101100000010…
…011000001111100111011
310221111110102100210002102
4100031200103001330323
5121222444101144011
62211434202054015
7143325154606544
oct20154023017473
93844412323072
101114012131131
1139a4a4895559
1215baa04aa30b
1381087a73a23
143bcc041b4cb
151dea0bcd73b
hex103604c1f3b

1114012131131 has 4 divisors (see below), whose sum is σ = 1114014845064. Its totient is φ = 1114009417200.

The previous prime is 1114012131097. The next prime is 1114012131139. The reversal of 1114012131131 is 1311312104111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1114012131131 - 234 = 1096832261947 is a prime.

It is a super-2 number, since 2×11140121311312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1114012131139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 600785 + ... + 1609026.

It is an arithmetic number, because the mean of its divisors is an integer number (278503711266).

Almost surely, 21114012131131 is an apocalyptic number.

1114012131131 is a deficient number, since it is larger than the sum of its proper divisors (2713933).

1114012131131 is an equidigital number, since it uses as much as digits as its factorization.

1114012131131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2713932.

The product of its (nonzero) digits is 72, while the sum is 20.

Adding to 1114012131131 its reverse (1311312104111), we get a palindrome (2425324235242).

The spelling of 1114012131131 in words is "one trillion, one hundred fourteen billion, twelve million, one hundred thirty-one thousand, one hundred thirty-one".

Divisors: 1 504121 2209811 1114012131131