111403114131 has 4 divisors (see below), whose sum is σ = 148537485512. Its totient is φ = 74268742752.

The previous prime is 111403114033. The next prime is 111403114139. The reversal of 111403114131 is 131411304111.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 131411304111 = 3 ⋅43803768037.

It is not a de Polignac number, because 111403114131 - 2¹⁷ = 111402983059 is a prime.

It is a super-2 number, since 2×111403114131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 111403114098 and 111403114107.

It is not an unprimeable number, because it can be changed into a prime (111403114139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18567185686 + ... + 18567185691.

It is an arithmetic number, because the mean of its divisors is an integer number (37134371378).

Almost surely, 2^111403114131 is an apocalyptic number.

111403114131 is a deficient number, since it is larger than the sum of its proper divisors (37134371381).

111403114131 is an equidigital number, since it uses as much as digits as its factorization.

111403114131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37134371380.

The product of its (nonzero) digits is 144, while the sum is 21.

Adding to 111403114131 its reverse (131411304111), we get a palindrome (242814418242).

The spelling of 111403114131 in words is "one hundred eleven billion, four hundred three million, one hundred fourteen thousand, one hundred thirty-one".