11140320113 has 8 divisors (see below), whose sum is σ = 12021709056. Its totient is φ = 10262422800.

The previous prime is 11140320109. The next prime is 11140320131. The reversal of 11140320113 is 31102304111.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11140320113 - 2² = 11140320109 is a prime.

It is a super-2 number, since 2×11140320113² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11140320091 and 11140320100.

It is not an unprimeable number, because it can be changed into a prime (11140320173) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 866273 + ... + 879038.

It is an arithmetic number, because the mean of its divisors is an integer number (1502713632).

Almost surely, 2^11140320113 is an apocalyptic number.

11140320113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11140320113 is a deficient number, since it is larger than the sum of its proper divisors (881388943).

11140320113 is a wasteful number, since it uses less digits than its factorization.

11140320113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1745815.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 11140320113 its reverse (31102304111), we get a palindrome (42242624224).

The spelling of 11140320113 in words is "eleven billion, one hundred forty million, three hundred twenty thousand, one hundred thirteen".