1114050121 has 4 divisors (see below), whose sum is σ = 1116001744. Its totient is φ = 1112098500.

The previous prime is 1114050097. The next prime is 1114050173. The reversal of 1114050121 is 1210504111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1210504111 = 2311 ⋅523801.

It is a cyclic number.

It is not a de Polignac number, because 1114050121 - 2⁹ = 1114049609 is a prime.

It is a super-2 number, since 2×1114050121² = 2482215344200229282, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1114050095 and 1114050104.

It is not an unprimeable number, because it can be changed into a prime (1114050181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 974955 + ... + 976096.

It is an arithmetic number, because the mean of its divisors is an integer number (279000436).

Almost surely, 2^1114050121 is an apocalyptic number.

It is an amenable number.

1114050121 is a deficient number, since it is larger than the sum of its proper divisors (1951623).

1114050121 is an equidigital number, since it uses as much as digits as its factorization.

1114050121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1951622.

The product of its (nonzero) digits is 40, while the sum is 16.

The square root of 1114050121 is about 33377.3893676543. The cubic root of 1114050121 is about 1036.6565833510.

Adding to 1114050121 its reverse (1210504111), we get a palindrome (2324554232).

The spelling of 1114050121 in words is "one billion, one hundred fourteen million, fifty thousand, one hundred twenty-one".