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1114055246433 = 32261316422047
BaseRepresentation
bin10000001101100010110…
…111100000001001100001
310221111120102111021011110
4100031202313200021201
5121223041120341213
62211442342133533
7143326220231253
oct20154267401141
93844512437143
101114055246433
1139a517163738
1215bab2a212a9
138109398b53c
143bcc6041cd3
151dea48985c3
hex10362de0261

1114055246433 has 8 divisors (see below), whose sum is σ = 1485472773888. Its totient is φ = 742670608304.

The previous prime is 1114055246419. The next prime is 1114055246443. The reversal of 1114055246433 is 3346425504111.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1114055246433 - 24 = 1114055246417 is a prime.

It is a super-2 number, since 2×11140552464332 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1114055246391 and 1114055246400.

It is not an unprimeable number, because it can be changed into a prime (1114055246413) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8143185 + ... + 8278862.

It is an arithmetic number, because the mean of its divisors is an integer number (185684096736).

Almost surely, 21114055246433 is an apocalyptic number.

It is an amenable number.

1114055246433 is a deficient number, since it is larger than the sum of its proper divisors (371417527455).

1114055246433 is a wasteful number, since it uses less digits than its factorization.

1114055246433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16444663.

The product of its (nonzero) digits is 172800, while the sum is 39.

The spelling of 1114055246433 in words is "one trillion, one hundred fourteen billion, fifty-five million, two hundred forty-six thousand, four hundred thirty-three".

Divisors: 1 3 22613 67839 16422047 49266141 371351748811 1114055246433