11141040000113 has 12 divisors (see below), whose sum is σ = 11470503678480. Its totient is φ = 10815184532376.

The previous prime is 11141040000029. The next prime is 11141040000121. The reversal of 11141040000113 is 31100004014111.

It is a de Polignac number, because none of the positive numbers 2^k-11141040000113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11141040000091 and 11141040000100.

It is not an unprimeable number, because it can be changed into a prime (11141040000133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3733403 + ... + 6018336.

It is an arithmetic number, because the mean of its divisors is an integer number (955875306540).

Almost surely, 2^{11141040000113} is an apocalyptic number.

It is an amenable number.

11141040000113 is a deficient number, since it is larger than the sum of its proper divisors (329463678367).

11141040000113 is an frugal number, since it uses more digits than its factorization.

11141040000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9752108 (or 9751945 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 11141040000113 its reverse (31100004014111), we get a palindrome (42241044014224).

The spelling of 11141040000113 in words is "eleven trillion, one hundred forty-one billion, forty million, one hundred thirteen", and thus it is an aban number.