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11141080364707 = 56209119820777
BaseRepresentation
bin1010001000011111110000…
…1000110011011010100011
31110110002002001020202211021
42202013330020303122203
52430013413033132312
635410050333230311
72226626233406056
oct242077410633243
943402061222737
1011141080364707
1136059a6467047
1212bb271332397
1362a7a3a805b7
142a7334470a9d
15144c12183c07
hexa21fc2336a3

11141080364707 has 4 divisors (see below), whose sum is σ = 11141100747576. Its totient is φ = 11141059981840.

The previous prime is 11141080364677. The next prime is 11141080364717. The reversal of 11141080364707 is 70746308014111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11141080364707 - 231 = 11138932881059 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11141080364717) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9348298 + ... + 10472479.

It is an arithmetic number, because the mean of its divisors is an integer number (2785275186894).

Almost surely, 211141080364707 is an apocalyptic number.

11141080364707 is a deficient number, since it is larger than the sum of its proper divisors (20382869).

11141080364707 is an equidigital number, since it uses as much as digits as its factorization.

11141080364707 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20382868.

The product of its (nonzero) digits is 112896, while the sum is 43.

Adding to 11141080364707 its reverse (70746308014111), we get a palindrome (81887388378818).

The spelling of 11141080364707 in words is "eleven trillion, one hundred forty-one billion, eighty million, three hundred sixty-four thousand, seven hundred seven".

Divisors: 1 562091 19820777 11141080364707