1114113440003 has 4 divisors (see below), whose sum is σ = 1116401147760. Its totient is φ = 1111825732248.

The previous prime is 1114113439997. The next prime is 1114113440047. The reversal of 1114113440003 is 3000443114111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1114113440003 - 2³⁶ = 1045393963267 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1114113440093) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1143853148 + ... + 1143854121.

It is an arithmetic number, because the mean of its divisors is an integer number (279100286940).

Almost surely, 2^{1114113440003} is an apocalyptic number.

1114113440003 is a deficient number, since it is larger than the sum of its proper divisors (2287707757).

1114113440003 is an equidigital number, since it uses as much as digits as its factorization.

1114113440003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2287707756.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1114113440003 its reverse (3000443114111), we get a palindrome (4114556554114).

The spelling of 1114113440003 in words is "one trillion, one hundred fourteen billion, one hundred thirteen million, four hundred forty thousand, three".