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1114134132403 = 10211091218543
BaseRepresentation
bin10000001101100111100…
…100011011011010110011
310221111202220221002101001
4100031213210123122303
5121223221314214103
62211454241022431
7143331165604435
oct20154744333263
93844686832331
101114134132403
1139a557743956
1215bb15324a17
13810a711b826
143bcd26d8655
151deab77c01d
hex1036791b6b3

1114134132403 has 4 divisors (see below), whose sum is σ = 1115225351968. Its totient is φ = 1113042912840.

The previous prime is 1114134132383. The next prime is 1114134132407. The reversal of 1114134132403 is 3042314314111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1114134132403 - 221 = 1114132035251 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1114134132407) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 545608251 + ... + 545610292.

It is an arithmetic number, because the mean of its divisors is an integer number (278806337992).

Almost surely, 21114134132403 is an apocalyptic number.

1114134132403 is a deficient number, since it is larger than the sum of its proper divisors (1091219565).

1114134132403 is a wasteful number, since it uses less digits than its factorization.

1114134132403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1091219564.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 1114134132403 its reverse (3042314314111), we get a palindrome (4156448446514).

The spelling of 1114134132403 in words is "one trillion, one hundred fourteen billion, one hundred thirty-four million, one hundred thirty-two thousand, four hundred three".

Divisors: 1 1021 1091218543 1114134132403