Base | Representation |
---|---|
bin | 10000001101101011100… |
… | …000001010101001100011 |
3 | 10221111221112002210211101 |
4 | 100031223200022221203 |
5 | 121223340212432003 |
6 | 2211504555255231 |
7 | 143332626534661 |
oct | 20155340125143 |
9 | 3844845083741 |
10 | 1114200124003 |
11 | 39a590a1736a |
12 | 15bb3344a517 |
13 | 810b79b5a05 |
14 | 3bcdb395c31 |
15 | 1deb246511d |
hex | 1036b80aa63 |
1114200124003 has 4 divisors (see below), whose sum is σ = 1129893083568. Its totient is φ = 1098507164440.
The previous prime is 1114200123961. The next prime is 1114200124007. The reversal of 1114200124003 is 3004210024111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1114200124003 - 217 = 1114199992931 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1114200124007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7846479676 + ... + 7846479817.
It is an arithmetic number, because the mean of its divisors is an integer number (282473270892).
Almost surely, 21114200124003 is an apocalyptic number.
1114200124003 is a deficient number, since it is larger than the sum of its proper divisors (15692959565).
1114200124003 is an equidigital number, since it uses as much as digits as its factorization.
1114200124003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15692959564.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 1114200124003 its reverse (3004210024111), we get a palindrome (4118410148114).
The spelling of 1114200124003 in words is "one trillion, one hundred fourteen billion, two hundred million, one hundred twenty-four thousand, three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •