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111420315433 = 715917187919
BaseRepresentation
bin110011111000100101…
…0110001011100101001
3101122121001222110212101
41213301022301130221
53311142100043213
6123104044013401
711023046024530
oct1476112613451
9348531873771
10111420315433
1143286955119
1219716531261
13a67883c53b
14556daa3317
152d71b51bdd
hex19f12b1729

111420315433 has 4 divisors (see below), whose sum is σ = 127337503360. Its totient is φ = 95503127508.

The previous prime is 111420315431. The next prime is 111420315439. The reversal of 111420315433 is 334513024111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 111420315433 - 21 = 111420315431 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (111420315431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7958593953 + ... + 7958593966.

It is an arithmetic number, because the mean of its divisors is an integer number (31834375840).

Almost surely, 2111420315433 is an apocalyptic number.

It is an amenable number.

111420315433 is a deficient number, since it is larger than the sum of its proper divisors (15917187927).

111420315433 is an equidigital number, since it uses as much as digits as its factorization.

111420315433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15917187926.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 111420315433 its reverse (334513024111), we get a palindrome (445933339544).

The spelling of 111420315433 in words is "one hundred eleven billion, four hundred twenty million, three hundred fifteen thousand, four hundred thirty-three".

Divisors: 1 7 15917187919 111420315433