Base | Representation |
---|---|
bin | 10100110000010010… |
… | …00101111000010011 |
3 | 1001202112111100111020 |
4 | 22120021011320103 |
5 | 140304432023203 |
6 | 5041353250523 |
7 | 543056205654 |
oct | 123011057023 |
9 | 31675440436 |
10 | 11142454803 |
11 | 47a8697237 |
12 | 21ab703a43 |
13 | 10875b412c |
14 | 779b9352b |
15 | 45332d153 |
hex | 298245e13 |
11142454803 has 8 divisors (see below), whose sum is σ = 14857837968. Its totient is φ = 7427687424.
The previous prime is 11142454801. The next prime is 11142454847. The reversal of 11142454803 is 30845424111.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11142454803 - 21 = 11142454801 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11142454801) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 109926 + ... + 185387.
It is an arithmetic number, because the mean of its divisors is an integer number (1857229746).
Almost surely, 211142454803 is an apocalyptic number.
11142454803 is a deficient number, since it is larger than the sum of its proper divisors (3715383165).
11142454803 is a wasteful number, since it uses less digits than its factorization.
11142454803 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 307893.
The product of its (nonzero) digits is 15360, while the sum is 33.
Adding to 11142454803 its reverse (30845424111), we get a palindrome (41987878914).
The spelling of 11142454803 in words is "eleven billion, one hundred forty-two million, four hundred fifty-four thousand, eight hundred three".
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