11143014441241 has 4 divisors (see below), whose sum is σ = 11143021536612. Its totient is φ = 11143007345872.

The previous prime is 11143014441233. The next prime is 11143014441269. The reversal of 11143014441241 is 14214441034111.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 10244128416025 + 898886025216 = 3200645^2 + 948096^2 .

It is a cyclic number.

It is not a de Polignac number, because 11143014441241 - 2³ = 11143014441233 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11143014441541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28066 + ... + 4720891.

It is an arithmetic number, because the mean of its divisors is an integer number (2785755384153).

Almost surely, 2^{11143014441241} is an apocalyptic number.

It is an amenable number.

11143014441241 is a deficient number, since it is larger than the sum of its proper divisors (7095371).

11143014441241 is an equidigital number, since it uses as much as digits as its factorization.

11143014441241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7095370.

The product of its (nonzero) digits is 6144, while the sum is 31.

Adding to 11143014441241 its reverse (14214441034111), we get a palindrome (25357455475352).

The spelling of 11143014441241 in words is "eleven trillion, one hundred forty-three billion, fourteen million, four hundred forty-one thousand, two hundred forty-one".