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11143040005435 = 513530932290711
BaseRepresentation
bin1010001000100111000011…
…1100001111010100111011
31110110021010121122211112111
42202021300330033110323
52430031421220133220
635411013015153151
72230025630155252
oct242116074172473
943407117584474
1011143040005435
113606811648138
1212bb7196757b7
1362aa26a66720
142a747c821799
15144cc922315a
hexa2270f0f53b

11143040005435 has 16 divisors (see below), whose sum is σ = 14402949180480. Its totient is φ = 8227156256640.

The previous prime is 11143040005429. The next prime is 11143040005463. The reversal of 11143040005435 is 53450004034111.

11143040005435 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 11143040005435 - 215 = 11143039972667 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11143040005397 and 11143040005406.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15800271 + ... + 16490440.

It is an arithmetic number, because the mean of its divisors is an integer number (900184323780).

Almost surely, 211143040005435 is an apocalyptic number.

11143040005435 is a deficient number, since it is larger than the sum of its proper divisors (3259909175045).

11143040005435 is a wasteful number, since it uses less digits than its factorization.

11143040005435 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32296038.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 11143040005435 its reverse (53450004034111), we get a palindrome (64593044039546).

The spelling of 11143040005435 in words is "eleven trillion, one hundred forty-three billion, forty million, five thousand, four hundred thirty-five".

Divisors: 1 5 13 65 5309 26545 69017 345085 32290711 161453555 419779243 2098896215 171431384699 857156923495 2228608001087 11143040005435