Base | Representation |
---|---|
bin | 1010001000100111000011… |
… | …1100001111010100111011 |
3 | 1110110021010121122211112111 |
4 | 2202021300330033110323 |
5 | 2430031421220133220 |
6 | 35411013015153151 |
7 | 2230025630155252 |
oct | 242116074172473 |
9 | 43407117584474 |
10 | 11143040005435 |
11 | 3606811648138 |
12 | 12bb7196757b7 |
13 | 62aa26a66720 |
14 | 2a747c821799 |
15 | 144cc922315a |
hex | a2270f0f53b |
11143040005435 has 16 divisors (see below), whose sum is σ = 14402949180480. Its totient is φ = 8227156256640.
The previous prime is 11143040005429. The next prime is 11143040005463. The reversal of 11143040005435 is 53450004034111.
11143040005435 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11143040005435 - 215 = 11143039972667 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11143040005397 and 11143040005406.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15800271 + ... + 16490440.
It is an arithmetic number, because the mean of its divisors is an integer number (900184323780).
Almost surely, 211143040005435 is an apocalyptic number.
11143040005435 is a deficient number, since it is larger than the sum of its proper divisors (3259909175045).
11143040005435 is a wasteful number, since it uses less digits than its factorization.
11143040005435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32296038.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 11143040005435 its reverse (53450004034111), we get a palindrome (64593044039546).
The spelling of 11143040005435 in words is "eleven trillion, one hundred forty-three billion, forty million, five thousand, four hundred thirty-five".
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