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1114333044113 = 1966156677333
BaseRepresentation
bin10000001101110011011…
…011001101110110010001
310221112021210012211221102
4100031303123031312101
5121224123224402423
62211530104234145
7143336132410112
oct20156333156621
93845253184842
101114333044113
1139a649a531a3
1215bb6ba6b955
13811093b4673
143bd10cb6209
151debde6dc28
hex103736cdd91

1114333044113 has 4 divisors (see below), whose sum is σ = 1114389741108. Its totient is φ = 1114276347120.

The previous prime is 1114333044103. The next prime is 1114333044179. The reversal of 1114333044113 is 3114403334111.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 667216149889 + 447116894224 = 816833^2 + 668668^2 .

It is a cyclic number.

It is not a de Polignac number, because 1114333044113 - 224 = 1114316266897 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1114333044103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28319006 + ... + 28358327.

It is an arithmetic number, because the mean of its divisors is an integer number (278597435277).

Almost surely, 21114333044113 is an apocalyptic number.

It is an amenable number.

1114333044113 is a deficient number, since it is larger than the sum of its proper divisors (56696995).

1114333044113 is an equidigital number, since it uses as much as digits as its factorization.

1114333044113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56696994.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 1114333044113 its reverse (3114403334111), we get a palindrome (4228736378224).

The spelling of 1114333044113 in words is "one trillion, one hundred fourteen billion, three hundred thirty-three million, forty-four thousand, one hundred thirteen".

Divisors: 1 19661 56677333 1114333044113