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11144113 = 17476379
BaseRepresentation
bin101010100000…
…101110110001
3202222011211221
4222200232301
510323102423
61034505041
7163503061
oct52405661
922864757
1011144113
116321812
123895181
132402566
1416a13a1
15ea1e5d
hexaa0bb1

11144113 has 4 divisors (see below), whose sum is σ = 11152240. Its totient is φ = 11135988.

The previous prime is 11144083. The next prime is 11144117. The reversal of 11144113 is 31144111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 11144113 - 213 = 11135921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11144117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1443 + ... + 4936.

It is an arithmetic number, because the mean of its divisors is an integer number (2788060).

Almost surely, 211144113 is an apocalyptic number.

It is an amenable number.

11144113 is a deficient number, since it is larger than the sum of its proper divisors (8127).

11144113 is an equidigital number, since it uses as much as digits as its factorization.

11144113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8126.

The product of its digits is 48, while the sum is 16.

The square root of 11144113 is about 3338.2799463197. The cubic root of 11144113 is about 223.3650238439.

Adding to 11144113 its reverse (31144111), we get a palindrome (42288224).

The spelling of 11144113 in words is "eleven million, one hundred forty-four thousand, one hundred thirteen".

Divisors: 1 1747 6379 11144113