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11144401331 = 71592057333
BaseRepresentation
bin10100110000100001…
…00001000110110011
31001202200011020121212
422120100201012303
5140310431320311
65041503110335
7543111563660
oct123020410663
931680136555
1011144401331
1147a97a6738
1221b02a23ab
131087b1611b
1477a13ca67
154535b4c8b
hex2984211b3

11144401331 has 4 divisors (see below), whose sum is σ = 12736458672. Its totient is φ = 9552343992.

The previous prime is 11144401321. The next prime is 11144401349. The reversal of 11144401331 is 13310444111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11144401331 - 26 = 11144401267 is a prime.

It is a super-2 number, since 2×111444013312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11144401297 and 11144401306.

It is not an unprimeable number, because it can be changed into a prime (11144401321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 796028660 + ... + 796028673.

It is an arithmetic number, because the mean of its divisors is an integer number (3184114668).

Almost surely, 211144401331 is an apocalyptic number.

11144401331 is a deficient number, since it is larger than the sum of its proper divisors (1592057341).

11144401331 is an equidigital number, since it uses as much as digits as its factorization.

11144401331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1592057340.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 11144401331 its reverse (13310444111), we get a palindrome (24454845442).

The spelling of 11144401331 in words is "eleven billion, one hundred forty-four million, four hundred one thousand, three hundred thirty-one".

Divisors: 1 7 1592057333 11144401331