11144441402131 has 4 divisors (see below), whose sum is σ = 11144451156264. Its totient is φ = 11144431648000.

The previous prime is 11144441402119. The next prime is 11144441402179. The reversal of 11144441402131 is 13120414444111.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 11144441402131 - 2¹¹ = 11144441400083 is a prime.

It is a super-2 number, since 2×11144441402131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11144441402093 and 11144441402102.

It is not an unprimeable number, because it can be changed into a prime (11144441403131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2894665 + ... + 5537866.

It is an arithmetic number, because the mean of its divisors is an integer number (2786112789066).

Almost surely, 2^{11144441402131} is an apocalyptic number.

11144441402131 is a deficient number, since it is larger than the sum of its proper divisors (9754133).

11144441402131 is an equidigital number, since it uses as much as digits as its factorization.

11144441402131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9754132.

The product of its (nonzero) digits is 6144, while the sum is 31.

Adding to 11144441402131 its reverse (13120414444111), we get a palindrome (24264855846242).

The spelling of 11144441402131 in words is "eleven trillion, one hundred forty-four billion, four hundred forty-one million, four hundred two thousand, one hundred thirty-one".