Base | Representation |
---|---|
bin | 10100110001000111… |
… | …11110100101110001 |
3 | 1001210000202102120101 |
4 | 22120203332211301 |
5 | 140313233042313 |
6 | 5042204312401 |
7 | 543203132110 |
oct | 123043764561 |
9 | 31700672511 |
10 | 11149502833 |
11 | 4801670557 |
12 | 21b1b42701 |
13 | 1088bb1171 |
14 | 77aaa9c77 |
15 | 453c715dd |
hex | 2988fe971 |
11149502833 has 4 divisors (see below), whose sum is σ = 12742288960. Its totient is φ = 9556716708.
The previous prime is 11149502831. The next prime is 11149502851. The reversal of 11149502833 is 33820594111.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 11149502833 - 21 = 11149502831 is a prime.
It is a super-2 number, since 2×111495028332 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11149502792 and 11149502801.
It is not an unprimeable number, because it can be changed into a prime (11149502831) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 796393053 + ... + 796393066.
It is an arithmetic number, because the mean of its divisors is an integer number (3185572240).
Almost surely, 211149502833 is an apocalyptic number.
It is an amenable number.
11149502833 is a deficient number, since it is larger than the sum of its proper divisors (1592786127).
11149502833 is an equidigital number, since it uses as much as digits as its factorization.
11149502833 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1592786126.
The product of its (nonzero) digits is 25920, while the sum is 37.
The spelling of 11149502833 in words is "eleven billion, one hundred forty-nine million, five hundred two thousand, eight hundred thirty-three".
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