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11163664404313 = 23485376713231
BaseRepresentation
bin1010001001110011111001…
…0000000100111101011001
31110112020100222002212000121
42202130332100010331121
52430401141041414223
635424303331433241
72231356003521121
oct242347620047531
943466328085017
1011163664404313
11361453557a293
121303714755821
1362c962900645
142a8477a01c81
151455d4bcb15d
hexa273e404f59

11163664404313 has 4 divisors (see below), whose sum is σ = 11649041117568. Its totient is φ = 10678287691060.

The previous prime is 11163664404311. The next prime is 11163664404317. The reversal of 11163664404313 is 31340446636111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11163664404313 - 21 = 11163664404311 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11163664404313.

It is not an unprimeable number, because it can be changed into a prime (11163664404311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 242688356593 + ... + 242688356638.

It is an arithmetic number, because the mean of its divisors is an integer number (2912260279392).

Almost surely, 211163664404313 is an apocalyptic number.

It is an amenable number.

11163664404313 is a deficient number, since it is larger than the sum of its proper divisors (485376713255).

11163664404313 is an equidigital number, since it uses as much as digits as its factorization.

11163664404313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 485376713254.

The product of its (nonzero) digits is 373248, while the sum is 43.

The spelling of 11163664404313 in words is "eleven trillion, one hundred sixty-three billion, six hundred sixty-four million, four hundred four thousand, three hundred thirteen".

Divisors: 1 23 485376713231 11163664404313