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11188130035 = 52237626007
BaseRepresentation
bin10100110101101110…
…10101000011110011
31001212201102220010111
422122313111003303
5140403130130120
65050104242151
7544152351625
oct123267250363
931781386114
1011188130035
114821453765
122202a70357
131093bb6bb4
14781c82c15
1545735175a
hex29add50f3

11188130035 has 4 divisors (see below), whose sum is σ = 13425756048. Its totient is φ = 8950504024.

The previous prime is 11188130011. The next prime is 11188130047. The reversal of 11188130035 is 53003188111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11188130035 - 25 = 11188130003 is a prime.

It is a super-3 number, since 3×111881300353 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11188129979 and 11188130006.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1118812999 + ... + 1118813008.

It is an arithmetic number, because the mean of its divisors is an integer number (3356439012).

Almost surely, 211188130035 is an apocalyptic number.

11188130035 is a deficient number, since it is larger than the sum of its proper divisors (2237626013).

11188130035 is an equidigital number, since it uses as much as digits as its factorization.

11188130035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2237626012.

The product of its (nonzero) digits is 2880, while the sum is 31.

The spelling of 11188130035 in words is "eleven billion, one hundred eighty-eight million, one hundred thirty thousand, thirty-five".

Divisors: 1 5 2237626007 11188130035