11200013013003 has 4 divisors (see below), whose sum is σ = 14933350684008. Its totient is φ = 7466675342000.

The previous prime is 11200013012999. The next prime is 11200013013031. The reversal of 11200013013003 is 30031031000211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11200013013003 - 2² = 11200013012999 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11200013213003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1866668835498 + ... + 1866668835503.

It is an arithmetic number, because the mean of its divisors is an integer number (3733337671002).

Almost surely, 2^{11200013013003} is an apocalyptic number.

11200013013003 is a deficient number, since it is larger than the sum of its proper divisors (3733337671005).

11200013013003 is an equidigital number, since it uses as much as digits as its factorization.

11200013013003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3733337671004.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 11200013013003 its reverse (30031031000211), we get a palindrome (41231044013214).

The spelling of 11200013013003 in words is "eleven trillion, two hundred billion, thirteen million, thirteen thousand, three".