Base | Representation |
---|---|
bin | 1010001011111100000010… |
… | …0011001110101001110011 |
3 | 1110122201200220110200122120 |
4 | 2202333000203032221303 |
5 | 2432001012302414303 |
6 | 35453145555005323 |
7 | 2234121435622662 |
oct | 242770043165163 |
9 | 43581626420576 |
10 | 11200210201203 |
11 | 3628a89740411 |
12 | 130a813899843 |
13 | 63323815c82a |
14 | 2aa143532dd9 |
15 | 146523300553 |
hex | a2fc08cea73 |
11200210201203 has 16 divisors (see below), whose sum is σ = 15034411480320. Its totient is φ = 7416443807136.
The previous prime is 11200210201199. The next prime is 11200210201261. The reversal of 11200210201203 is 30210201200211.
11200210201203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11200210201203 - 22 = 11200210201199 is a prime.
It is a super-2 number, since 2×112002102012032 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (11200210201273) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3245073 + ... + 5738546.
It is an arithmetic number, because the mean of its divisors is an integer number (939650717520).
Almost surely, 211200210201203 is an apocalyptic number.
11200210201203 is a deficient number, since it is larger than the sum of its proper divisors (3834201279117).
11200210201203 is a wasteful number, since it uses less digits than its factorization.
11200210201203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8986426.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 11200210201203 its reverse (30210201200211), we get a palindrome (41410411401414).
The spelling of 11200210201203 in words is "eleven trillion, two hundred billion, two hundred ten million, two hundred one thousand, two hundred three".
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