1120021311113 has 4 divisors (see below), whose sum is σ = 1121763180048. Its totient is φ = 1118279442180.

The previous prime is 1120021311091. The next prime is 1120021311119. The reversal of 1120021311113 is 3111131200211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1120021311113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1120021311091 and 1120021311100.

It is not an unprimeable number, because it can be changed into a prime (1120021311119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 870933503 + ... + 870934788.

It is an arithmetic number, because the mean of its divisors is an integer number (280440795012).

Almost surely, 2^{1120021311113} is an apocalyptic number.

It is an amenable number.

1120021311113 is a deficient number, since it is larger than the sum of its proper divisors (1741868935).

1120021311113 is an equidigital number, since it uses as much as digits as its factorization.

1120021311113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1741868934.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 1120021311113 its reverse (3111131200211), we get a palindrome (4231152511324).

The spelling of 1120021311113 in words is "one trillion, one hundred twenty billion, twenty-one million, three hundred eleven thousand, one hundred thirteen".