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112013113 = 195895427
BaseRepresentation
bin1101010110100…
…10111100111001
321210202212002211
412223102330321
5212133404423
615040455121
72530044562
oct653227471
9253685084
10112013113
1158257123
123161a4a1
131a28b764
1410c3b169
159c7910d
hex6ad2f39

112013113 has 4 divisors (see below), whose sum is σ = 117908560. Its totient is φ = 106117668.

The previous prime is 112013089. The next prime is 112013149. The reversal of 112013113 is 311310211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 112013113 - 25 = 112013081 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 112013093 and 112013102.

It is not an unprimeable number, because it can be changed into a prime (112013183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2947695 + ... + 2947732.

It is an arithmetic number, because the mean of its divisors is an integer number (29477140).

Almost surely, 2112013113 is an apocalyptic number.

It is an amenable number.

112013113 is a deficient number, since it is larger than the sum of its proper divisors (5895447).

112013113 is an equidigital number, since it uses as much as digits as its factorization.

112013113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5895446.

The product of its (nonzero) digits is 18, while the sum is 13.

The square root of 112013113 is about 10583.6247571425. The cubic root of 112013113 is about 482.0472641221.

Adding to 112013113 its reverse (311310211), we get a palindrome (423323324).

The spelling of 112013113 in words is "one hundred twelve million, thirteen thousand, one hundred thirteen".

Divisors: 1 19 5895427 112013113