112026113 has 4 divisors (see below), whose sum is σ = 112515540. Its totient is φ = 111536688.

The previous prime is 112026023. The next prime is 112026127. The reversal of 112026113 is 311620211.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 311620211 = 7 ⋅44517173.

It can be written as a sum of positive squares in 2 ways, for example, as 48553024 + 63473089 = 6968^2 + 7967^2 .

It is a cyclic number.

It is not a de Polignac number, because 112026113 - 2¹² = 112022017 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 112026091 and 112026100.

It is not an unprimeable number, because it can be changed into a prime (112026163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 244370 + ... + 244827.

It is an arithmetic number, because the mean of its divisors is an integer number (28128885).

Almost surely, 2^112026113 is an apocalyptic number.

It is an amenable number.

112026113 is a deficient number, since it is larger than the sum of its proper divisors (489427).

112026113 is an equidigital number, since it uses as much as digits as its factorization.

112026113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 489426.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 112026113 is about 10584.2388956410. The cubic root of 112026113 is about 482.0659118555.

Adding to 112026113 its reverse (311620211), we get a palindrome (423646324).

The spelling of 112026113 in words is "one hundred twelve million, twenty-six thousand, one hundred thirteen".