112030100433121 has 4 divisors (see below), whose sum is σ = 120647800466452. Its totient is φ = 103412400399792.

The previous prime is 112030100433107. The next prime is 112030100433169. The reversal of 112030100433121 is 121334001030211.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 72582970750096 + 39447129683025 = 8519564^2 + 6280695^2 .

It is a cyclic number.

It is not a de Polignac number, because 112030100433121 - 2⁹ = 112030100432609 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 112030100433092 and 112030100433101.

It is not an unprimeable number, because it can be changed into a prime (112030100433421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4308850016646 + ... + 4308850016671.

It is an arithmetic number, because the mean of its divisors is an integer number (30161950116613).

Almost surely, 2^{112030100433121} is an apocalyptic number.

It is an amenable number.

112030100433121 is a deficient number, since it is larger than the sum of its proper divisors (8617700033331).

112030100433121 is an equidigital number, since it uses as much as digits as its factorization.

112030100433121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8617700033330.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 112030100433121 its reverse (121334001030211), we get a palindrome (233364101463332).

The spelling of 112030100433121 in words is "one hundred twelve trillion, thirty billion, one hundred million, four hundred thirty-three thousand, one hundred twenty-one".