11204013311131 has 8 divisors (see below), whose sum is σ = 11316414320640. Its totient is φ = 11091990121128.

The previous prime is 11204013311017. The next prime is 11204013311159. The reversal of 11204013311131 is 13111331040211.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11204013311131 - 2²¹ = 11204011213979 is a prime.

It is a super-3 number, since 3×11204013311131³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11204013311431) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 94395271 + ... + 94513888.

It is an arithmetic number, because the mean of its divisors is an integer number (1414551790080).

Almost surely, 2^{11204013311131} is an apocalyptic number.

11204013311131 is a deficient number, since it is larger than the sum of its proper divisors (112401009509).

11204013311131 is a wasteful number, since it uses less digits than its factorization.

11204013311131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 188909753.

The product of its (nonzero) digits is 216, while the sum is 22.

Adding to 11204013311131 its reverse (13111331040211), we get a palindrome (24315344351342).

The spelling of 11204013311131 in words is "eleven trillion, two hundred four billion, thirteen million, three hundred eleven thousand, one hundred thirty-one".