Base | Representation |
---|---|
bin | 10100110111101010… |
… | …11111010110100001 |
3 | 1001220212002202210012 |
4 | 22123311133112201 |
5 | 140421313100441 |
6 | 5051445414305 |
7 | 544441020311 |
oct | 123365372641 |
9 | 31825082705 |
10 | 11204425121 |
11 | 482a67347a |
12 | 220840a395 |
13 | 10973a0b66 |
14 | 7840c5441 |
15 | 4589be9eb |
hex | 29bd5f5a1 |
11204425121 has 4 divisors (see below), whose sum is σ = 11205102000. Its totient is φ = 11203748244.
The previous prime is 11204425117. The next prime is 11204425159. The reversal of 11204425121 is 12152440211.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 12152440211 = 263 ⋅46206997.
It is a cyclic number.
It is not a de Polignac number, because 11204425121 - 22 = 11204425117 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11204425171) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 312971 + ... + 346928.
It is an arithmetic number, because the mean of its divisors is an integer number (2801275500).
Almost surely, 211204425121 is an apocalyptic number.
It is an amenable number.
11204425121 is a deficient number, since it is larger than the sum of its proper divisors (676879).
11204425121 is an equidigital number, since it uses as much as digits as its factorization.
11204425121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 676878.
The product of its (nonzero) digits is 640, while the sum is 23.
Adding to 11204425121 its reverse (12152440211), we get a palindrome (23356865332).
The spelling of 11204425121 in words is "eleven billion, two hundred four million, four hundred twenty-five thousand, one hundred twenty-one".
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