Base | Representation |
---|---|
bin | 110100001011010110… |
… | …0111100011000100011 |
3 | 101201012221220022000101 |
4 | 1220112230330120203 |
5 | 3313434301430430 |
6 | 123250341003231 |
7 | 11044463353432 |
oct | 1502654743043 |
9 | 351187808011 |
10 | 112050030115 |
11 | 4357a359081 |
12 | 198713b3517 |
13 | a74914028a |
14 | 55cd583119 |
15 | 2dac08ddca |
hex | 1a16b3c623 |
112050030115 has 4 divisors (see below), whose sum is σ = 134460036144. Its totient is φ = 89640024088.
The previous prime is 112050030091. The next prime is 112050030119. The reversal of 112050030115 is 511030050211.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 511030050211 = 71 ⋅7197606341.
It is a cyclic number.
It is not a de Polignac number, because 112050030115 - 211 = 112050028067 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 112050030092 and 112050030101.
It is not an unprimeable number, because it can be changed into a prime (112050030119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11205003007 + ... + 11205003016.
It is an arithmetic number, because the mean of its divisors is an integer number (33615009036).
Almost surely, 2112050030115 is an apocalyptic number.
112050030115 is a deficient number, since it is larger than the sum of its proper divisors (22410006029).
112050030115 is an equidigital number, since it uses as much as digits as its factorization.
112050030115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22410006028.
The product of its (nonzero) digits is 150, while the sum is 19.
Adding to 112050030115 its reverse (511030050211), we get a palindrome (623080080326).
The spelling of 112050030115 in words is "one hundred twelve billion, fifty million, thirty thousand, one hundred fifteen".
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