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1121005403 = 71153138893
BaseRepresentation
bin100001011010001…
…0010111101011011
32220010100222022122
41002310102331123
54243434133103
6303123011455
736531250220
oct10264227533
92803328278
101121005403
11525861a51
12273509b8b
1314b32690b
14a8c49947
1568634b38
hex42d12f5b

1121005403 has 8 divisors (see below), whose sum is σ = 1282269408. Its totient is φ = 960021504.

The previous prime is 1121005397. The next prime is 1121005481. The reversal of 1121005403 is 3045001211.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1121005403 - 28 = 1121005147 is a prime.

It is a super-2 number, since 2×11210054032 = 2513306227110384818, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1121005493) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 61376 + ... + 77517.

It is an arithmetic number, because the mean of its divisors is an integer number (160283676).

Almost surely, 21121005403 is an apocalyptic number.

1121005403 is a deficient number, since it is larger than the sum of its proper divisors (161264005).

1121005403 is a wasteful number, since it uses less digits than its factorization.

1121005403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 140053.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 1121005403 is about 33481.4187722086. The cubic root of 1121005403 is about 1038.8094744057.

Adding to 1121005403 its reverse (3045001211), we get a palindrome (4166006614).

The spelling of 1121005403 in words is "one billion, one hundred twenty-one million, five thousand, four hundred three".

Divisors: 1 7 1153 8071 138893 972251 160143629 1121005403