Base | Representation |
---|---|
bin | 10000010100000010010… |
… | …101000111011001111011 |
3 | 10222011120012100120122120 |
4 | 100110002111013121323 |
5 | 121331330020212133 |
6 | 2214554140052323 |
7 | 143664025662633 |
oct | 20240225073173 |
9 | 3864505316576 |
10 | 1121025554043 |
11 | 3a2473777a3a |
12 | 1613192340a3 |
13 | 81934a99505 |
14 | 3c387a6d6c3 |
15 | 1e261799ab3 |
hex | 1050254767b |
1121025554043 has 4 divisors (see below), whose sum is σ = 1494700738728. Its totient is φ = 747350369360.
The previous prime is 1121025554041. The next prime is 1121025554053. The reversal of 1121025554043 is 3404555201211.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1121025554043 - 21 = 1121025554041 is a prime.
It is a super-2 number, since 2×11210255540432 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1121025553995 and 1121025554013.
It is not an unprimeable number, because it can be changed into a prime (1121025554041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 186837592338 + ... + 186837592343.
It is an arithmetic number, because the mean of its divisors is an integer number (373675184682).
Almost surely, 21121025554043 is an apocalyptic number.
1121025554043 is a deficient number, since it is larger than the sum of its proper divisors (373675184685).
1121025554043 is an equidigital number, since it uses as much as digits as its factorization.
1121025554043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 373675184684.
The product of its (nonzero) digits is 24000, while the sum is 33.
The spelling of 1121025554043 in words is "one trillion, one hundred twenty-one billion, twenty-five million, five hundred fifty-four thousand, forty-three".
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