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112103312113 = 1310383721667
BaseRepresentation
bin110100001100111100…
…0001100101011110001
3101201100200011022011201
41220121320030223301
53314041421441423
6123255523011201
711046011300512
oct1503170145361
9351320138151
10112103312113
11435a7440691
1219887209b01
13a7571a74a0
1455d6692a09
152db1ab62ad
hex1a19e0caf1

112103312113 has 8 divisors (see below), whose sum is σ = 121898748608. Its totient is φ = 102475319184.

The previous prime is 112103312107. The next prime is 112103312141. The reversal of 112103312113 is 311213301211.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 112103312113 - 221 = 112101214961 is a prime.

It is not an unprimeable number, because it can be changed into a prime (112103312183) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 41859495 + ... + 41862172.

It is an arithmetic number, because the mean of its divisors is an integer number (15237343576).

Almost surely, 2112103312113 is an apocalyptic number.

112103312113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

112103312113 is a deficient number, since it is larger than the sum of its proper divisors (9795436495).

112103312113 is a wasteful number, since it uses less digits than its factorization.

112103312113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 83721783.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 112103312113 its reverse (311213301211), we get a palindrome (423316613324).

The spelling of 112103312113 in words is "one hundred twelve billion, one hundred three million, three hundred twelve thousand, one hundred thirteen".

Divisors: 1 13 103 1339 83721667 1088381671 8623331701 112103312113