112111313001 has 4 divisors (see below), whose sum is σ = 149481750672. Its totient is φ = 74740875332.

The previous prime is 112111312987. The next prime is 112111313009. The reversal of 112111313001 is 100313111211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 112111313001 - 2¹⁵ = 112111280233 is a prime.

It is not an unprimeable number, because it can be changed into a prime (112111313009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18685218831 + ... + 18685218836.

It is an arithmetic number, because the mean of its divisors is an integer number (37370437668).

Almost surely, 2^112111313001 is an apocalyptic number.

It is an amenable number.

112111313001 is a deficient number, since it is larger than the sum of its proper divisors (37370437671).

112111313001 is an equidigital number, since it uses as much as digits as its factorization.

112111313001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37370437670.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 112111313001 its reverse (100313111211), we get a palindrome (212424424212).

The spelling of 112111313001 in words is "one hundred twelve billion, one hundred eleven million, three hundred thirteen thousand, one".