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11211202200003 = 3131032790939059
BaseRepresentation
bin1010001100100100111110…
…1110011000000111000011
31110200210001221212002022020
42203021033232120013003
52432141020230400003
635502204415412523
72234661020232501
oct243111756300703
943623057762266
1011211202200003
11363270a403843
121310980b24143
1363429a515330
142aa8a731d671
1514696830dd53
hexa324fb981c3

11211202200003 has 16 divisors (see below), whose sum is σ = 16254429085440. Its totient is φ = 6832218813984.

The previous prime is 11211202199929. The next prime is 11211202200047. The reversal of 11211202200003 is 30000220211211.

It is not a de Polignac number, because 11211202200003 - 214 = 11211202183619 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11211202200703) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1395465513 + ... + 1395473546.

It is an arithmetic number, because the mean of its divisors is an integer number (1015901817840).

Almost surely, 211211202200003 is an apocalyptic number.

11211202200003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

11211202200003 is a deficient number, since it is larger than the sum of its proper divisors (5043226885437).

11211202200003 is a wasteful number, since it uses less digits than its factorization.

11211202200003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2790939178.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 11211202200003 its reverse (30000220211211), we get a palindrome (41211422411214).

The spelling of 11211202200003 in words is "eleven trillion, two hundred eleven billion, two hundred two million, two hundred thousand, three".

Divisors: 1 3 13 39 103 309 1339 4017 2790939059 8372817177 36282207767 108846623301 287466723077 862400169231 3737067400001 11211202200003