Base | Representation |
---|---|
bin | 11001011111011100100010… |
… | …100100000101001011000011 |
3 | 112200221210221210102020202202 |
4 | 121133130202210011023003 |
5 | 104143321100432224303 |
6 | 1034235332021103415 |
7 | 32420555425555025 |
oct | 3137344244051303 |
9 | 480853853366682 |
10 | 112112111211203 |
11 | 327a4530027334 |
12 | 106a80b3257b6b |
13 | 4a7318554750c |
14 | 1d9838013c015 |
15 | ce645ed16c88 |
hex | 65f7229052c3 |
112112111211203 has 4 divisors (see below), whose sum is σ = 112472600315088. Its totient is φ = 111751622107320.
The previous prime is 112112111211193. The next prime is 112112111211209. The reversal of 112112111211203 is 302112111211211.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 112112111211203 - 24 = 112112111211187 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (112112111211209) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 180244551476 + ... + 180244552097.
It is an arithmetic number, because the mean of its divisors is an integer number (28118150078772).
Almost surely, 2112112111211203 is an apocalyptic number.
112112111211203 is a deficient number, since it is larger than the sum of its proper divisors (360489103885).
112112111211203 is an equidigital number, since it uses as much as digits as its factorization.
112112111211203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 360489103884.
The product of its (nonzero) digits is 48, while the sum is 20.
Adding to 112112111211203 its reverse (302112111211211), we get a palindrome (414224222422414).
The spelling of 112112111211203 in words is "one hundred twelve trillion, one hundred twelve billion, one hundred eleven million, two hundred eleven thousand, two hundred three".
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