Base | Representation |
---|---|
bin | 110100001101001110… |
… | …1100010011000011001 |
3 | 101201101100120121001122 |
4 | 1220122131202120121 |
5 | 3314101423202223 |
6 | 123300512455025 |
7 | 11046160425524 |
oct | 1503235423031 |
9 | 351340517048 |
10 | 112113100313 |
11 | 43601a16705 |
12 | 1988a54a475 |
13 | a759223816 |
14 | 55d7abdbbb |
15 | 2db289b5c8 |
hex | 1a1a762619 |
112113100313 has 16 divisors (see below), whose sum is σ = 117334855680. Its totient is φ = 107002026000.
The previous prime is 112113100289. The next prime is 112113100343. The reversal of 112113100313 is 313001311211.
It is a cyclic number.
It is not a de Polignac number, because 112113100313 - 218 = 112112838169 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 112113100291 and 112113100300.
It is not an unprimeable number, because it can be changed into a prime (112113100343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 564506 + ... + 736812.
It is an arithmetic number, because the mean of its divisors is an integer number (7333428480).
Almost surely, 2112113100313 is an apocalyptic number.
It is an amenable number.
112113100313 is a deficient number, since it is larger than the sum of its proper divisors (5221755367).
112113100313 is a wasteful number, since it uses less digits than its factorization.
112113100313 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 172628.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 112113100313 its reverse (313001311211), we get a palindrome (425114411524).
The spelling of 112113100313 in words is "one hundred twelve billion, one hundred thirteen million, one hundred thousand, three hundred thirteen".
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