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112113221203 = 451612482523
BaseRepresentation
bin110100001101001110…
…1111111111001010011
3101201101100210201220001
41220122131333321103
53314101441034303
6123300515230431
711046161441134
oct1503235777123
9351340721801
10112113221203
1143601a99515
121988a5a8417
13a759266859
1455d7b11c8b
152db28c231d
hex1a1a77fe53

112113221203 has 4 divisors (see below), whose sum is σ = 112115748888. Its totient is φ = 112110693520.

The previous prime is 112113221201. The next prime is 112113221219. The reversal of 112113221203 is 302122311211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 112113221203 - 21 = 112113221201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (112113221201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1196101 + ... + 1286422.

It is an arithmetic number, because the mean of its divisors is an integer number (28028937222).

Almost surely, 2112113221203 is an apocalyptic number.

112113221203 is a deficient number, since it is larger than the sum of its proper divisors (2527685).

112113221203 is an equidigital number, since it uses as much as digits as its factorization.

112113221203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2527684.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 112113221203 its reverse (302122311211), we get a palindrome (414235532414).

The spelling of 112113221203 in words is "one hundred twelve billion, one hundred thirteen million, two hundred twenty-one thousand, two hundred three".

Divisors: 1 45161 2482523 112113221203