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11211324113 = 111019211283
BaseRepresentation
bin10100111000011111…
…10011101011010001
31001221100002021102102
422130033303223101
5140430044332423
65052253330145
7544553453063
oct123417635321
931840067372
1011211324113
114833555820
12220a796955
1310989480c2
14784d9d733
154593d3c28
hex29c3f3ad1

11211324113 has 4 divisors (see below), whose sum is σ = 12230535408. Its totient is φ = 10192112820.

The previous prime is 11211324001. The next prime is 11211324133. The reversal of 11211324113 is 31142311211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11211324113 - 28 = 11211323857 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11211324133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 509605631 + ... + 509605652.

It is an arithmetic number, because the mean of its divisors is an integer number (3057633852).

Almost surely, 211211324113 is an apocalyptic number.

It is an amenable number.

11211324113 is a deficient number, since it is larger than the sum of its proper divisors (1019211295).

11211324113 is a wasteful number, since it uses less digits than its factorization.

11211324113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1019211294.

The product of its digits is 144, while the sum is 20.

Adding to 11211324113 its reverse (31142311211), we get a palindrome (42353635324).

The spelling of 11211324113 in words is "eleven billion, two hundred eleven million, three hundred twenty-four thousand, one hundred thirteen".

Divisors: 1 11 1019211283 11211324113