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11211433 = 431272053
BaseRepresentation
bin101010110001…
…001010101001
3210002121012021
4222301022221
510332231213
61040144441
7164203252
oct52611251
923077167
1011211433
116368352
123908121
1324270ac
1416bbb29
15eb6d8d
hexab12a9

11211433 has 8 divisors (see below), whose sum is σ = 11568128. Its totient is φ = 10859184.

The previous prime is 11211401. The next prime is 11211437. The reversal of 11211433 is 33411211.

11211433 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11211433 - 25 = 11211401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11211437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4435 + ... + 6487.

It is an arithmetic number, because the mean of its divisors is an integer number (1446016).

Almost surely, 211211433 is an apocalyptic number.

It is an amenable number.

11211433 is a deficient number, since it is larger than the sum of its proper divisors (356695).

11211433 is a wasteful number, since it uses less digits than its factorization.

11211433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2223.

The product of its digits is 72, while the sum is 16.

The square root of 11211433 is about 3348.3478015284. The cubic root of 11211433 is about 223.8138933039.

Adding to 11211433 its reverse (33411211), we get a palindrome (44622644).

The spelling of 11211433 in words is "eleven million, two hundred eleven thousand, four hundred thirty-three".

Divisors: 1 43 127 2053 5461 88279 260731 11211433