Base | Representation |
---|---|
bin | 1010001100101000011001… |
… | …1111101111111000110001 |
3 | 1110200212102222221122202002 |
4 | 2203022012133233320301 |
5 | 2432144411001041423 |
6 | 35502435523103345 |
7 | 2235022545656525 |
oct | 243120637577061 |
9 | 43625388848662 |
10 | 11212121112113 |
11 | 3633041083039 |
12 | 1310b98811b55 |
13 | 6343b5a00bcc |
14 | 2aa95339dd85 |
15 | 1469bdd24228 |
hex | a32867efe31 |
11212121112113 has 8 divisors (see below), whose sum is σ = 11395979586816. Its totient is φ = 11028264354000.
The previous prime is 11212121112083. The next prime is 11212121112131. The reversal of 11212121112113 is 31121112121211.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11212121112113 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (11212121112713) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24834038 + ... + 25281488.
It is an arithmetic number, because the mean of its divisors is an integer number (1424497448352).
Almost surely, 211212121112113 is an apocalyptic number.
It is an amenable number.
11212121112113 is a deficient number, since it is larger than the sum of its proper divisors (183858474703).
11212121112113 is an equidigital number, since it uses as much as digits as its factorization.
11212121112113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 858295.
The product of its digits is 48, while the sum is 20.
Adding to 11212121112113 its reverse (31121112121211), we get a palindrome (42333233233324).
The spelling of 11212121112113 in words is "eleven trillion, two hundred twelve billion, one hundred twenty-one million, one hundred twelve thousand, one hundred thirteen".
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